A) \[2\]
B) \[\frac{1}{4}\]
C) \[1\]
D) \[0\]
Correct Answer: C
Solution :
[c] According to the question, \[\because \] ABCD is a rectangle \[\therefore \] \[\angle \,DAC=\frac{90{}^\circ }{2}=45{}^\circ \] \[\therefore \] \[(ta{{n}^{2}}\,\angle \,CAD+1)\,si{{n}^{2}}\,\angle \,BAC\] \[=(ta{{n}^{2}}45{}^\circ +1)\ si{{n}^{2}}45{}^\circ \] \[={{\left( 1+1\times \frac{1}{\sqrt{2}} \right)}^{2}}\] \[=2\times \frac{1}{2}=1\] |
You need to login to perform this action.
You will be redirected in
3 sec