A) 3 : 4
B) 4 : 3
C) 5 : 4
D) 4 : 5
Correct Answer: B
Solution :
[b] In a cyclic quadrilateral Sum of opposite angles \[=\text{ }180{}^\circ \] So, \[4x+5y=7x+y=180{}^\circ \] or \[4x+5y=7x+y\] \[5y-y=7x-x,\]\[4y-3x,\]\[\frac{4}{3}=\frac{x}{y}\] or \[\frac{x}{y}=\frac{4}{3}\] \[\therefore \] \[x:y=4:3\] |
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