A) \[{{60}^{{}^\circ }}\]
B) \[{{75}^{{}^\circ }}\]
C) \[{{45}^{{}^\circ }}\]
D) \[{{50}^{{}^\circ }}\]
Correct Answer: C
Solution :
(c): \[\angle C=\angle A={{75}^{{}^\circ }}\] (Opposite \[\angle s\] of aligm) In \[\Delta BCD\], \[\angle CBD+\angle BCD+\angle BDC={{180}^{{}^\circ }}\] \[\angle ADB={{60}^{{}^\circ }}\]- alternate angle \[\angle ABD={{45}^{{}^\circ }}\] Then, \[\angle BDC={{45}^{{}^\circ }}\]- alternate angleYou need to login to perform this action.
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