A) \[4\sqrt{2}\]cm.
B) 5 cm
C) 6 cm.
D) 10 cm.
Correct Answer: B
Solution :
(b): \[QC=18\]cm. \[AC=\sqrt{C{{R}^{2}}+A{{R}^{2}}}=\sqrt{{{6}^{2}}+{{8}^{2}}}=\sqrt{36+64}\] \[=\sqrt{100}=10\]cm. \[BD=DC;\,\,\,BE=EA\] \[\therefore \]\[DE\parallel AC\] and \[DE=\frac{1}{2}AC=\frac{10}{2}=5\].cmYou need to login to perform this action.
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