9th Class Mathematics Quadrilaterals Question Bank Quadrilaterals

  • question_answer
    In the parallelogram\[ABCD\], \[AP\] and \[BP\] are bisectors of\[\angle A\]and\[\angle B\]which meet at\[P\]. What is \[2\angle APB\] equivalent to?

    A) \[\angle A+\angle B\]                 

    B) \[\angle A+\angle C\]     

    C)        \[\angle B+\angle D\]     

    D)        \[\angle A-\angle D\]

    Correct Answer: A

    Solution :

    \[\angle 2+\angle 3+\angle APB={{180}^{o}}\] \[\Rightarrow \]\[\angle 1+\angle 4+\angle APB={{180}^{o}}\] (Since \[\angle 2=\angle 1\]and\[\angle 3=\angle 4.\]) \[\Rightarrow \]\[2\angle 1+2\angle 3+2\angle APB={{360}^{o}}\] \[\Rightarrow \]\[\angle APB=\angle A+\angle B\]


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