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9th Class Mathematics Quadrilaterals Question Bank Quadrilaterals

  • question_answer
    In parallelogram\[ABCD,\] \[AB=12\,\,cm\]. The altitudes corresponding to the sides \[AB\] and \[AD\] are respectively \[9\,\,cm\] and\[11\,\,cm\]. Find\[AD\].

    A) \[\frac{108}{11}cm\]                 

    B) \[\frac{108}{10}cm\]     

    C)        \[\frac{99}{10}cm\]       

    D)        \[\frac{108}{17}cm\]                 

    Correct Answer: A

    Solution :

    Area of parallelogram with base AB and attitude AM \[=12\times 9=108\,c{{m}^{2}}\] \[108\,c{{m}^{2}}=AD\times 11\,cm\] \[\Rightarrow \]\[AD=\frac{108}{11}\,cm\]


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