A) \[\angle x-\angle y\]
B) \[\angle x+\angle y\]
C) \[\angle x+\angle 2y\]
D) none of these
Correct Answer: B
Solution :
(b): Join BD: \[\angle \text{1}+\angle 2=\angle y\] \[\angle 3+\angle 4=\angle x\] In \[{{\Delta }^{1e}}\] ABD \[\angle b=\angle 1+\angle 3\] (exterior angle= sum of interior \[\angle s\]) Similarly, in \[{{\Delta }^{1e}}BCD,\] \[\angle a=\angle 2+\angle 4\] Adding \[\angle b+\angle a=\angle 1+\angle 2+\angle 3+\angle 4\] \[\Rightarrow \angle a+\angle b=\angle x+\angle y.\]You need to login to perform this action.
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