A) \[{{47}^{{}^\circ }},{{133}^{{}^\circ }},{{47}^{{}^\circ }},{{133}^{{}^\circ }}\]
B) \[{{80}^{{}^\circ }},{{100}^{{}^\circ }},{{80}^{{}^\circ }},{{100}^{{}^\circ }}\]
C) \[{{77}^{{}^\circ }},{{103}^{{}^\circ }},{{77}^{{}^\circ }},{{103}^{{}^\circ }}\]
D) \[{{94}^{{}^\circ }},{{86}^{{}^\circ }},{{94}^{{}^\circ }},{{86}^{{}^\circ }}\]
Correct Answer: A
Solution :
(a): Opposite \[\angle s\] of parallelogram are equal. \[\Rightarrow 3x+5=61-x\] \[\Rightarrow 4x=56=x={{14}^{{}^\circ }}\] \[\Rightarrow 3x+5={{47}^{{}^\circ }}.\] Adjacent \[{{\Delta }^{1e}}={{180}^{{}^\circ }}-{{47}^{{}^\circ }}={{133}^{{}^\circ }}\] \[\Delta \,are\,{{47}^{{}^\circ }},{{133}^{{}^\circ }},{{47}^{{}^\circ }},{{133}^{{}^\circ }}\]You need to login to perform this action.
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