A) \[10\sqrt{2}m\]
B) \[4\sqrt{2}m\]
C) \[5\sqrt{2}m\]
D) \[6\sqrt{2}m\]
Correct Answer: D
Solution :
(d) Draw SM perpendicular to QR, where M is a point on QR. In triangle SMR, we need to find SM. SM=SR x sin45 = \[12x\frac{1}{\sqrt{2}}=6\sqrt{2}\]You need to login to perform this action.
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