question_answer

If \[PQ\] and \[RS\] are two perpendicular diameters of a circle, what is\[PRQS\]?

A)  A rectangle

B)         A trapezium

C)         A square

D)         A rhombus but not a square

Correct Answer: C

Solution :

Let the diagonals meet at O as shown in the figure. \[\angle POS=\angle ROQ={{90}^{o}}\] Also \[OP=OQ=OS=OR,\]ie., the diagonals are equal and bisect at right angles. Clearly PRQS is square.