A) \[{{70}^{o}}\]
B) \[{{90}^{o}}\]
C) \[{{80}^{o}}\]
D) None of these
Correct Answer: D
Solution :
Since, sum of all angles of a quadrilateral is \[{{360}^{o}}.\] \[\therefore \]\[x+x+{{20}^{o}}+x-{{40}^{o}}+2x={{360}^{o}}\] \[\Rightarrow \]\[5x={{360}^{o}}-{{20}^{o}}+{{40}^{o}}={{380}^{o}}\] \[\Rightarrow \]\[x={{76}^{o}}\] \[\therefore \]Angles are \[{{76}^{o}},{{96}^{o}},{{36}^{o}}\]and \[{{152}^{o}}\] \[\therefore \]Required difference \[={{152}^{o}}-{{36}^{o}}={{116}^{o}}\]You need to login to perform this action.
You will be redirected in
3 sec