A) \[CR=\frac{1}{3}CB\]
B) CR= RB
C) \[CR=\frac{1}{2}RB\]
D) None of these
Correct Answer: B
Solution :
Join B and D. Suppose AC and BD intersect at O. Then. \[OC=\frac{1}{2}AC\] Now, \[CQ=\frac{1}{4}AC\][Given] \[\Rightarrow \]\[CQ=\frac{1}{2}OC\] In \[\Delta COD,P\]and Q are the mid-points of DC and OC respectively. \[\therefore \]\[PQ|DO\] [By mid-point theorem] Also, in \[\Delta COB,Q\]is the mid-point of OC and \[QR||OB\] \[\therefore \] R is the mid-point of BC. [By converse of mid-point theorem] \[\Rightarrow \]CR = RBYou need to login to perform this action.
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