A) \[{{135}^{o}}\]
B) \[{{144}^{o}}\]
C) \[{{154}^{o}}\]
D) \[{{108}^{o}}\]
Correct Answer: B
Solution :
Given that, \[\angle A:\angle B:\angle C:\angle D=1:2:3:4\] Let \[\angle A={{x}^{o}},\] \[\angle B=2{{x}^{o}},\angle C=3{{x}^{o}},\angle D=4{{x}^{o}},\] \[\therefore \]\[\angle A+\angle B+\angle C+\angle D={{360}^{o}}\] Thus the angles are \[\angle A={{36}^{o}},\] \[\angle B=(2\times {{36}^{o}})={{72}^{o}},\] \[\angle C=(3\times {{36}^{o}})={{108}^{o}}\]and \[\angle D=(4{{x}^{o}})=(4\times {{36}^{o}})={{144}^{o}}\]
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