A) \[x+y=a+b\]
B) \[x-y=a-b\]
C) \[\frac{x-y}{2}=a-b\]
D) \[2(x+y)=a+b\]
Correct Answer: A
Solution :
Join BD. In \[\Delta \Alpha \Beta D,\]we have \[\angle ABD+\angle ADB=b\] ?(i) In\[\Delta CBD,\] we have \[\angle CBD+\angle CDB=a\] ?(ii) Adding (i) and (ii), we get \[(\angle ABD+\angle CBD)+(\angle ADB+\angle CDB)\]\[=a+b\] \[\Rightarrow \]\[x+y=a+b\]You need to login to perform this action.
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