A) \[{{60}^{o}},\,\,{{120}^{o}},\,\,{{60}^{o}},\,\,{{120}^{o}}\]
B) \[{{90}^{o}},\,\,{{90}^{o}},\,\,{{90}^{o}}\]
C) \[{{80}^{o}},\,\,{{100}^{o}},\,\,{{80}^{o}},\,\,{{100}^{o}}\]
D) \[{{30}^{o}},\,\,{{150}^{o}},\,\,{{30}^{o}},\,\,{{100}^{o}}\]
Correct Answer: C
Solution :
Let one angle be \[x.\] \[\therefore \]\[\frac{4}{5}x=\]another angle Now, \[x+\frac{4x}{5}={{180}^{o}}\] \[\Rightarrow \]\[x={{100}^{o}}\] \[\therefore \]\[\frac{4x}{5}=\frac{4}{5}\times {{100}^{o}}={{80}^{o}}\]
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