A) n-3 l-0 m-0 s- 1/2
B) n-3 l-2 m- ? 2 s- 1/2
C) n-4 l-0 m- 0 s- ½
D) n-4 l-1 m- ?1 s- ½
Correct Answer: C
Solution :
19th electron of chromium is \[4{{s}^{1}}\] \[n=4,\ l=0,\ m=0,\ s=+\frac{1}{2}\]You need to login to perform this action.
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