A) One unpaired electron
B) Two unpaired electrons
C) Three unpaired electrons
D) Four unpaired electrons
Correct Answer: B
Solution :
Atomic number 14 leaving 2 unpaired electron \[_{14}Si=1{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{2}}\]You need to login to perform this action.
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