A) \[n=4,\,l=3,\,m=+1,\,s=+\frac{1}{2}\]
B) \[n=4,\,l=4,\,m=-4,\,s=-\frac{1}{2}\]
C) \[n=4,\,l=3,\,m=+4,\,s=+\frac{1}{2}\]
D) \[n=3,\,l=2,\,m=-2,\,s=+\frac{1}{2}\]
Correct Answer: A
Solution :
For 4f orbital electron, \[n=4\] \[l=3\] (Because 0, 1, 2, 3) s, p, d, f m = + 3, + 2, +1, 0, ? 1, ? 2, ? 3 s = +1/2You need to login to perform this action.
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