A) \[Z{{n}^{+}}\]
B) \[F{{e}^{2+}}\]
C) \[{{N}^{3+}}\]
D) \[C{{u}^{+}}\]
Correct Answer: B
Solution :
\[F{{e}^{2+}}\,[Ar]\,3{{d}^{6}}4{{s}^{0}}\] \[F{{e}^{2+}}\]consist of maximum 4 unpaired electrons.You need to login to perform this action.
You will be redirected in
3 sec