A) 80 metres
B) 100 metres
C) 140 metres
D) 260 metres
Correct Answer: B
Solution :
Explanation: The movements of the child from A to E are as shown in figure. Clearly, the child meets his father at E. Now, \[AF=\left( AB-FB \right)\] \[\left( AB-DC \right)=\left( 90-30 \right)m=60\text{ }m.\] \[EF=\left( DE-DF \right)\] \[=\left( DE-BC \right)=\left( 100-20 \right)m=20\text{ }m.\] Required distance \[AE\,\,=\,\,\sqrt{{{60}^{2}}+{{80}^{2}}}\,\,=\,\,100m\]You need to login to perform this action.
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