A) \[\frac{10}{21}\]
B) \[\frac{11}{21}\]
C) \[\frac{2}{7}\]
D) \[\frac{5}{7}\]
E) None of these
Correct Answer: A
Solution :
Explanation Option (a) is correct. Total number of balls = (2 + 3 + 4) = 7 Let S be the sample space. Then, n (S) = Number of ways of drawing 2 balls out of 7 \[^{7}{{C}_{2}}=\frac{(7\times 6)}{(2\times 1)}=21\] Let E = Event of drawing 2 balls, none of which is blue. \[\therefore \] n (E) = Number of ways of drawing 2 balls out of (2 + 3) balls \[{{=}^{5}}{{C}_{2}}\frac{(5\times 4)}{(2\times 1)}=10\] \[\therefore \] \[P(E)=\frac{n(E)}{n(S)}=\frac{10}{21}.\]
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