A) \[{{15}^{o}}C\]
B) \[{{20}^{o}}C\][L1]
C) \[{{25}^{o}}C\]
D) \[{{10}^{o}}C\]
Correct Answer: B
Solution :
In first case \[\frac{50-40}{5}=K\left[ \frac{50+40}{2}-{{\theta }_{0}} \right]\] ?.(i) In second case \[\frac{40-33.33}{5}=K\left[ \frac{40+33.33}{2}-\theta \right]\] ?.(ii) By solving \[{{\theta }_{0}}={{20}^{o}}C\].You need to login to perform this action.
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