A) 42oC
B) 40oC
C) 56oC
D) 55oC
Correct Answer: A
Solution :
\[\frac{62-50}{10}=K\left( \frac{62+50}{2}-26 \right)\]Þ \[\frac{6}{5}=K\times 30\] Þ \[K=\frac{1}{25}\] And, \[\frac{50-\theta }{10}=\frac{1}{25}\left( \frac{50+\theta }{2}-26 \right)\] Þ \[\theta =42{}^\circ \]C.You need to login to perform this action.
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