JEE Main & Advanced Physics Transmission of Heat Question Bank Radiation Stefan's law

  • question_answer
    The temperature of a piece of iron is \[{{27}^{o}}C\] and it is radiating energy at the rate of \[Q\ kW{{m}^{-2}}\]. If its temperature is raised to \[{{151}^{o}}C\], the rate of radiation of energy will become approximately                                         [MP PET 1992]

    A)            \[2Q\ kW{{m}^{-2}}\]       

    B)            \[4Q\ kW{{m}^{-2}}\]

    C)            \[6Q\ kW{{m}^{-2}}\]       

    D)            \[8Q\ kW{{m}^{-2}}\]

    Correct Answer: B

    Solution :

               \[{{E}_{2}}={{E}_{1}}\frac{T_{2}^{4}}{T_{1}^{4}}=Q\times \frac{{{(273+151)}^{4}}}{{{(273+27)}^{4}}}={{\left( \frac{424}{300} \right)}^{4}}=3.99Q\approx 4Q\]


You need to login to perform this action.
You will be redirected in 3 sec spinner