JEE Main & Advanced Physics Transmission of Heat Question Bank Radiation Stefan's law

  • question_answer
    The temperatures of two bodies A and B are \[{{727}^{o}}C\] and \[{{127}^{o}}C\]. The ratio of rate of emission of radiations will be [MP PET 1986]

    A)            727/127                                  

    B)            625/16

    C)            1000/400                                

    D)            100/16

    Correct Answer: B

    Solution :

               \[\frac{{{E}_{1}}}{{{E}_{2}}}={{\left( \frac{{{T}_{1}}}{{{T}_{2}}} \right)}^{4}}={{\left( \frac{727+273}{127+273} \right)}^{4}}\]\[=\frac{{{(1000)}^{4}}}{{{(400)}^{4}}}=\frac{{{10}^{4}}}{{{4}^{4}}}=\frac{625}{16}\]


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