A) \[160\ kcal/{{m}^{2}}\ min\]
B) \[40\ kcal/{{m}^{2}}\ min\]
C) \[320\ kcal/{{m}^{2}}\ min\]
D) \[80\ kcal/{{m}^{2}}\ min\]
Correct Answer: C
Solution :
\[\frac{{{E}_{2}}}{{{E}_{1}}}={{\left( \frac{{{T}_{2}}}{{{T}_{1}}} \right)}^{4}}\]Þ\[\frac{{{E}_{2}}}{20}={{\left( \frac{2T}{T} \right)}^{4}}\]=16 Þ \[{{E}_{2}}=320\ kcal/{{m}^{2}}\]min.
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