A) 225
B) 450
C) 900
D) 1800
Correct Answer: D
Solution :
Radiated power by blackbody \[P=\frac{Q}{t}=A\sigma {{T}^{4}}\] Þ \[P\propto A{{T}^{4}}\]\[\propto {{r}^{2}}{{T}^{4}}\] Þ \[\frac{{{P}_{1}}}{{{P}_{2}}}={{\left( \frac{{{r}_{1}}}{{{r}_{2}}} \right)}^{2}}\,{{\left( \frac{{{T}_{1}}}{{{T}_{2}}} \right)}^{4}}\] Þ \[\frac{440}{{{P}_{2}}}={{\left( \frac{12}{6} \right)}^{2}}\,{{\left( \frac{500}{1000} \right)}^{4}}\] Þ\[{{P}_{2}}=1760\,W\approx 1800\,W\]
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