A) 16
B) 8
C) 4
D) 2
Correct Answer: A
Solution :
\[\frac{{{E}_{2}}}{{{E}_{1}}}=\frac{T_{2}^{4}}{T_{1}^{4}}={{\left( \frac{237+227}{273+27} \right)}^{4}}={{\left( \frac{600}{300} \right)}^{4}}=16\]
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