A) \[\frac{3}{8}E\]
B) \[\frac{81}{16}E\]
C) \[\frac{9}{16}E\]
D) \[\frac{81}{64}E\]
Correct Answer: D
Solution :
\[{{(Q)}_{Black\,body}}=A\sigma {{T}^{4}}t\] Þ \[\frac{Q}{t}\propto \]\[P=A\sigma {{T}^{4}}\] Breadth are halved so area becomes one fourth. Þ \[\frac{{{P}_{1}}}{{{P}_{2}}}=\frac{{{A}_{1}}}{{{A}_{2}}}\times {{\left( \frac{{{T}_{1}}}{{{T}_{2}}} \right)}^{4}}\] Þ \[\frac{{{A}_{1}}}{({{A}_{1}}/4)}\times \left( \frac{273+327}{273+127} \right)\] Þ \[{{P}_{2}}=\frac{81}{64}E\]
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