A) 80
B) 160
C) 250
D) 500
Correct Answer: A
Solution :
\[\frac{{{E}_{2}}}{{{E}_{1}}}={{\left( \frac{{{T}_{2}}}{{{T}_{1}}} \right)}^{4}}\]\[=\left( \frac{273+727}{237+227} \right)=\frac{{{(1000)}^{4}}}{{{(500)}^{4}}}=16\Rightarrow {{E}_{2}}=80\]You need to login to perform this action.
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