A) 3 Q
B) 9 Q
C) 27 Q
D) 81 Q
Correct Answer: D
Solution :
Power radiated \[P\propto {{T}^{4}}\] Þ \[\frac{{{P}_{1}}}{{{P}_{2}}}={{\left( \frac{{{T}_{1}}}{{{T}_{2}}} \right)}^{4}}\] Þ \[\frac{Q}{{{P}_{2}}}={{\left( \frac{T}{3T} \right)}^{4}}\] Þ \[{{P}_{2}}=81Q\]
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