A) 32 KJ
B) 320 KJ
C) 1200 KJ
D) None of these
Correct Answer: A
Solution :
\[\frac{{{Q}_{2}}}{{{Q}_{1}}}={{\left( \frac{{{T}_{2}}}{{{T}_{1}}} \right)}^{4}}={{\left( \frac{273+927}{273+327} \right)}^{4}}={{\left( \frac{1200}{600} \right)}^{4}}=16\] Þ Q2 \[=32\ KJ\]You need to login to perform this action.
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