A) 16.0
B) 10.45
C) 4.0
D) 2.0
Correct Answer: A
Solution :
\[\frac{{{Q}_{2}}}{{{Q}_{1}}}=\frac{T_{2}^{4}}{T_{1}^{4}}={{\left( \frac{273+527}{273+127} \right)}^{4}}={{\left( \frac{800}{400} \right)}^{4}}\]Þ\[{{Q}_{2}}=16\frac{cal}{c{{m}^{2}}\times s}\]You need to login to perform this action.
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