A) 125%
B) 200%
C) 300%
D) 400%
Correct Answer: D
Solution :
\[Q\propto {{T}^{4}}\] Þ \[\frac{{{Q}_{1}}}{{{Q}_{2}}}={{\left( \frac{{{T}_{1}}}{{{T}_{2}}} \right)}^{4}}\] Þ \[\frac{{{Q}_{1}}}{{{Q}_{2}}}={{\left( \frac{T}{T+T/2} \right)}^{4}}=\frac{16}{81}\] Þ \[{{Q}_{2}}=\frac{81}{16}{{Q}_{1}}\] % increase in energy \[=\frac{{{Q}_{2}}-{{Q}_{1}}}{{{Q}_{1}}}\times 100=400%\]
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