A) \[\frac{16}{3}R\]
B) \[2R\]
C) \[3R\]
D) \[\frac{2}{3}R\]
Correct Answer: A
Solution :
Rate of cooling \[\propto ({{T}^{4}}-T_{0}^{4})\]Þ \[\frac{{{R}_{1}}}{{{R}_{2}}}=\frac{(T_{1}^{4}-T_{0}^{4})}{(T_{2}^{4}-T_{0}^{4})}\] Þ\[\frac{R}{{{R}_{2}}}=\frac{{{(600)}^{4}}-{{(300)}^{4}}}{{{(900)}^{4}}-{{(300)}^{4}}}\]or \[{{R}_{2}}=\frac{16}{3}R\]
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