JEE Main & Advanced Physics Transmission of Heat Question Bank Radiation Stefan's law

  • question_answer
    The ratio of radiant energies radiated per unit surface area by two bodies is 16 : 1, the temperature of hotter body is 1000K, then the temperature of colder body will be  [UPSEAT 2001]

    A)            250 K                                       

    B)             500 K

    C)            1000 K                                     

    D)             62.5 K

    Correct Answer: B

    Solution :

                       \[Q\propto {{T}^{4}}\]Þ \[\frac{{{Q}_{1}}}{{{Q}_{2}}}=\frac{T_{1}^{4}}{T_{2}^{4}}\]Þ \[T_{2}^{4}=\left( \frac{{{E}_{2}}}{{{E}_{1}}} \right)T_{1}^{4}\]            Þ \[T_{2}^{4}=\frac{1}{16}\times {{(1000)}^{4}}={{\left( \frac{1000}{2} \right)}^{4}}\]Þ \[{{T}_{2}}=500K\]


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