A) \[3.33\ \mu m\]
B) \[0.66\ \mu m\]
C) \[1\ \mu m\]
D) \[1\ m\]
Correct Answer: A
Solution :
\[\therefore \]\[\frac{{{\lambda }_{{{m}_{2}}}}}{{{\lambda }_{{{m}_{1}}}}}=\frac{{{T}_{1}}}{{{T}_{2}}}\]\[\Rightarrow {{\lambda }_{{{m}_{2}}}}=\frac{2000}{2400}\times 4=3.33\ \mu m\]
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