A) 100 K
B) 150 K
C) 200 K
D) 250 K
Correct Answer: C
Solution :
\[\frac{{{T}_{2}}}{{{T}_{1}}}=\frac{{{\lambda }_{{{m}_{1}}}}}{{{\lambda }_{{{m}_{2}}}}}=\frac{1.75}{14.35}\Rightarrow {{T}_{2}}=\frac{1.75}{14.35}\times 1640=200\ K\]
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