JEE Main & Advanced Physics Transmission of Heat Question Bank Radiation Wein's law

  • question_answer
    The maximum wavelength of radiations emitted at 900 K is \[4\mu m\]. What will be the maximum wavelength of radiations emitted at 1200 K                                       [BHU 2002]

    A)            \[3\mu m\]                           

    B)            \[0.3\mu m\]

    C)            \[1\mu m\]                           

    D)            \[1\,\,m\]

    Correct Answer: A

    Solution :

               \[\frac{{{\lambda }_{2}}}{{{\lambda }_{1}}}=\frac{{{T}_{1}}}{{{T}_{2}}}\Rightarrow {{\lambda }_{2}}=\frac{{{T}_{1}}}{{{T}_{2}}}\times {{\lambda }_{1}}=\frac{900}{1200}\times 4=3\mu m\]


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