A) \[7325\,K\]
B) \[80000K\]
C) \[{{10}^{4}}\,K\]
D) \[{{10}^{6}}\,K\]
Correct Answer: A
Solution :
\[{{\lambda }_{m}}=\frac{b}{T}\Rightarrow T=\frac{b}{{{\lambda }_{m}}}=\frac{2.93\times {{10}^{-3}}}{4000\times {{10}^{-10}}}=7325\ K\]
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