A) \[{{(t)}_{1/2}}=\log 2\]
B) \[{{(t)}_{1/2}}=\frac{\lambda }{\log 2}\]
C) \[{{(t)}_{1/2}}=\frac{\lambda }{\log \,\text{2}}(2.303)\]
D) \[{{(t)}_{1/2}}=\frac{2.303\text{ log 2}}{\lambda }\]
Correct Answer: D
Solution :
\[{{T}_{1/2}}=\frac{{{\log }_{e}}2}{\lambda }=\frac{2.303{{\log }_{10}}2}{\lambda }\]
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