A) \[\frac{2{{\varepsilon }_{0}}hc}{{{e}^{2}}}\]
B) \[\beta ,\ \alpha ,\ \gamma \]
C) \[\gamma ,\ \alpha ,\ \beta \]
D) \[\beta ,\ \gamma ,\ \alpha \]
Correct Answer: B
Solution :
\[_{Z}{{X}^{A}}\xrightarrow{_{-1}{{\beta }^{0}}}{{\,}_{Z+1}}{{Y}^{A}}\xrightarrow{2H{{e}^{4}}(\alpha )}\]\[{{\,}_{Z-1}}{{K}^{A-4}}\xrightarrow{_{0}{{\gamma }^{0}}}{{\,}_{Z-1}}{{K}^{A-4}}\]
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