A) \[3\times {{10}^{10}}\] disintegrations/sec
B) \[3.7\times {{10}^{7}}\] disintegrations/sec
C) \[5\times {{10}^{7}}\] disintegrations/sec
D) \[3.7\times {{10}^{10}}\] disintegrations/sec
Correct Answer: D
Solution :
Complete reaction will be as follows \[_{92}{{X}^{235}}{{\to }_{82}}{{Y}^{207}}+{{7}_{2}}H{{e}^{4}}+{{4}_{-1}}{{e}^{0}}\] i.e., seven \[\alpha -\]particles and four \[\beta -\]particles will be emitted.
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