A) 5,000
B) 25,000
C) 12,500
D) 20,000
Correct Answer: C
Solution :
\[_{Z}{{X}^{A}}\xrightarrow{_{-1}{{\beta }^{0}}}{{\,}_{Z+1}}{{Y}^{A}}\xrightarrow{2H{{e}^{4}}(\alpha )}\]\[{{\,}_{Z-1}}{{K}^{A-4}}\xrightarrow{_{0}{{\gamma }^{0}}}{{\,}_{Z-1}}{{K}^{A-4}}\]
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