A) 6 and 7 half lives
B) 7 and 8 half lives
C) 8 and 9 half lives
D) 9 half lives
Correct Answer: A
Solution :
\[N={{N}_{0}}{{\left( \frac{1}{2} \right)}^{n}}\Rightarrow \frac{N}{{{N}_{0}}}={{\left( \frac{1}{2} \right)}^{n}}\]\[\Rightarrow \frac{1}{100}={{\left( \frac{1}{2} \right)}^{n}}\Rightarrow {{2}^{n}}=100\] n comes out in between 6 and 7.
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