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JEE Main & Advanced Physics Nuclear Physics And Radioactivity Question Bank Radioactivity

  • question_answer
    In the disintegration series        \[_{92}^{238}U\xrightarrow{\alpha }x\xrightarrow{\beta }_{Z}^{A}y\] The value of Z and A respectively will be [MP PET 2001; MP PMT 2001]

    A)            92, 236                                    

    B)            88, 230

    C)            90, 234                                    

    D)            91, 234

    Correct Answer: D

    Solution :

                       \[_{92}{{U}^{238}}{{\to }_{2}}H{{e}^{4}}{{+}_{90}}{{X}^{234}}{{\to }_{-1}}{{e}^{0}}{{+}_{91}}{{U}^{234}}\] Hence, A = 234, Z = 91


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