A) 69.3%
B) 63%
C) 50%
D) 37%
Correct Answer: B
Solution :
Number of atoms remains undecayed \[N={{N}_{0}}{{e}^{-\lambda t}}\] Number of atoms decayed = \[{{N}_{0}}(1-{{e}^{-\lambda t}})\] \[=\,{{N}_{0}}\,\left( 1-{{e}^{-\lambda \times \frac{1}{\lambda }}} \right)={{N}_{0}}\left( 1-\frac{1}{e} \right)\]\[=0.63\,{{N}_{0}}=63%\] of N0 .
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