JEE Main & Advanced Physics Nuclear Physics And Radioactivity Question Bank Radioactivity

  • question_answer
    If \[_{92}{{U}^{238}}\] undergoes successively 8 a-decays and 6 b-decays, then resulting nucleus is        [CBSE PMT 2002]

    A)            \[_{82}{{U}^{206}}\]         

    B)            \[_{82}P{{b}^{206}}\]

    C)            \[_{82}{{U}^{210}}\]         

    D)            \[_{82}{{U}^{214}}\]

    Correct Answer: B

    Solution :

                       \[_{(Z=92)}{{U}^{(A=238)}}{{\xrightarrow{(8\alpha ,\,6\beta )}}_{{{Z}'}}}{{X}^{{{A}'}}}\] so \[{A}'=A-4{{n}_{\alpha }}\]= 238 ? 4 ´ 8 = 206 and \[{Z}'={{n}_{\beta }}-2{{n}_{\alpha }}+z\]= 6 ? 2 ´ 8 + 92 = 82.


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