A) \[8\,\alpha ,\,7\beta \]
B) \[4\,\alpha ,\,7\beta \]
C) \[4\,\alpha ,\,4\beta \]
D) \[4\,\alpha ,\,1\beta \]
Correct Answer: D
Solution :
\[{{n}_{\alpha }}=\frac{228-212}{4}=4\] and \[{{n}_{\beta }}=2\times 4-90+83=1\]
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