JEE Main & Advanced Physics Nuclear Physics And Radioactivity Question Bank Radioactivity

  • question_answer
    A radioactive sample at any instant has its disintegration rate 5000 disintegration per minute. After 5 minutes, the rate is 1250 disintegrations per minute. Then, the decay constant (per minute) is                                           [AIEEE 2003]

    A)            0.8 In 2                                    

    B)            0.4 In 2

    C)            0.2 In 2                                    

    D)            0.1 In 2

    Correct Answer: B

    Solution :

               \[\lambda =\frac{{{\log }_{e}}\frac{{{A}_{1}}}{{{A}_{2}}}}{t}=\frac{{{\log }_{e}}\frac{5000}{1250}}{5}\]= 0.4 In 2 


You need to login to perform this action.
You will be redirected in 3 sec spinner