A) 0.8 In 2
B) 0.4 In 2
C) 0.2 In 2
D) 0.1 In 2
Correct Answer: B
Solution :
\[\lambda =\frac{{{\log }_{e}}\frac{{{A}_{1}}}{{{A}_{2}}}}{t}=\frac{{{\log }_{e}}\frac{5000}{1250}}{5}\]= 0.4 In 2You need to login to perform this action.
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